A coil has 600 turns which produces `5 xx 10^-3 Wb//turn` of flux when `3 A` current flows in the wire. This produced `6 xx 10^-3` Wb/turn in 1000 turns secondary coil. When the opened, the current drops to zero in `0.2 s` in primary. Find
(a) mutual inductance,
(b) the induced emf in the secondary,
(c) the self-inductance of the primary coil.

Explanation

To solve the problem step by step, we will calculate the mutual inductance, the induced emf in the secondary coil, and the self-inductance of the primary coil.

### Given Data:
- Number of turns in primary coil (N1) = 600 turns
- Flux per turn in primary coil (Φ1) = \(5 \times 10^{-3} \, \text{Wb}\)
- Current in primary coil (I1) = 3 A
- Number of turns in secondary coil (N2) = 1000 turns
- Flux per turn in secondary coil (Φ2) = \(6 \times 10^{-3} \, \text{Wb}\)
...