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In an LC circuit the capacitor has maxim...

In an `LC` circuit the capacitor has maximum charge `q_0`. The value of `((dI)/(dt))_(max)` is

A

`q_0/(LC)`

B

`q_0/sqrt(LC)`

C

`q_0/(LC)-1`

D

`q_0/(LC)+1`

Text Solution

Verified by Experts

The correct Answer is:
A
`(V_C)_(max) =(V_L)_(max)`
`q_0/C=L((dI)/(dt))_(max)`
`:. ((dI)/(dt))_(max)=q_0/(LC)`
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