Home
Class 12
PHYSICS
Assertion: In displacement method of fin...

Assertion: In displacement method of finding focal length of a convex lens its magnification in one position of lens is `+2,` then magnification in another position of lens should be `-1/2.`
Reason:This method can't be applied for a concave lens.

A

If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of the Assertion.

C

If both Assertion is true, but the Reason is false.

D

If both Assertion is false but the Reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that in the displacement method of finding the focal length of a convex lens, if the magnification in one position of the lens is +2, then the magnification in another position of the lens should be -1/2. - In the displacement method, the relationship between the magnifications (m1 and m2) at two different positions of the lens is given by the equation: \[ m_1 \times m_2 = -1 \] - If we let \( m_1 = +2 \), we can find \( m_2 \): \[ 2 \times m_2 = -1 \implies m_2 = -\frac{1}{2} \] - Thus, the assertion is true. 2. **Understanding the Reason**: - The reason states that the displacement method cannot be applied to a concave lens. - This is true because the displacement method relies on the fact that the magnification can be positive or negative depending on the position of the object and the image. For a concave lens, the image formed is always virtual and upright, leading to a positive magnification. Therefore, the relationship \( m_1 \times m_2 = -1 \) cannot be satisfied for a concave lens. - Hence, the reason is also true. 3. **Conclusion**: - Both the assertion and the reason are true. - However, the reason does not correctly explain the assertion, as the assertion is specifically about the magnification relationship for a convex lens. ### Final Answer: - Both the assertion and the reason are true, but the reason is not the correct explanation for the assertion. ---

To solve the question, we need to analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that in the displacement method of finding the focal length of a convex lens, if the magnification in one position of the lens is +2, then the magnification in another position of the lens should be -1/2. - In the displacement method, the relationship between the magnifications (m1 and m2) at two different positions of the lens is given by the equation: \[ ...
Promotional Banner

Topper's Solved these Questions

  • REFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Level 1 Objective|38 Videos
  • REFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Objective Questions|1 Videos
  • REFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Exercise 31.8|8 Videos
  • REFLECTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Subjective|9 Videos
  • SEMICONDUCTORS

    DC PANDEY ENGLISH|Exercise Subjective|12 Videos

Similar Questions

Explore conceptually related problems

Calculate focal length of given lens if the magnification is -0.5 .

Focal length of concave lens shown in figure is 60 cm. Find image position and its magnification.

In displacement method distance of object from convex lens of focal length 20 cm in one position 60 cm. Then

Focal length of a convex lense in air is 20cm. and of concave lens 40cm. Find the position of final image.

In question 118, if m_(1) and m_(2) are the magnifications for two positions of the lens, then

The focal length of a converging lens is 8 cm. Fins the magnification power when it is used as a reading lens to form the image at near point.

Focal length of the convex lens shown in figure is 20cm. Find the image position and image velocity.

In the displacement method , a convex lens is placed in between an object and a screen . If one of them magnification is 3 and the displacement of the lens between the two positions is 24 cm , then the focal length of the lens is :-

In a displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the separations of the magnified and diminished image position of the lens.

Distance of an object from a concave lens of focal length 20 cm is 40 cm. Then linear magnification of the image