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In YDSE, D = 1.2m and d= 0.25cm, the sli...

In YDSE, D = 1.2m and d= 0.25cm, the slits are illuminated with coherent 600nm light. Calculate the distance y above the central maximum for which the average intensity on the screen is 75% of the maximum.

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To solve the problem step by step, we will use the principles of Young's Double Slit Experiment (YDSE) and the relationship between intensity, phase difference, and path difference. ### Step 1: Understand the relationship between intensity and phase difference The intensity \( I \) at any point on the screen in YDSE is given by: \[ I = I_{\text{max}} \cos^2\left(\frac{\Phi}{2}\right) \] where \( \Phi \) is the phase difference between the two waves arriving at that point. ...
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