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Slit 1 of a double slit is wider than sl...

Slit 1 of a double slit is wider than slit 2, so that the light from slit 1 has an amplitudes three times that of the light from slit 2. Show that equation `I=I_(max) "cos"^2 phi/2` is replaced by the equation,
`I = (I_(max)/4(1+3cos^2(phi/2))` .

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To solve the problem, we need to derive the new intensity equation for a double-slit interference pattern when the amplitudes of the light from the two slits are different. ### Step-by-Step Solution: 1. **Define Amplitudes**: Let the amplitude of light from slit 2 be \( A_2 = a_0 \). Since the amplitude from slit 1 is three times that of slit 2, we have: \[ A_1 = 3A_2 = 3a_0 ...
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