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The central fringe of the interference p...

The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of 4th dark fringe after a glass sheet of refractive index 1.5 is introduced. The thickness of glass sheet would be

A

`4.8 mu m`

B

`4.2 mu m`

C

`5.4 mu m `

D

`3.0 mu m `

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow the reasoning provided in the video transcript. ### Step 1: Understand the Shift of the Central Fringe The central fringe shifts to the position of the 4th dark fringe when a glass sheet is introduced. The path difference for the dark fringes is given by the formula: \[ \text{Path difference} = \left(n + \frac{1}{2}\right) \lambda \] where \( n \) is the order of the dark fringe. For the 4th dark fringe, \( n = 3 \): \[ \text{Path difference} = \left(3 + \frac{1}{2}\right) \lambda = \frac{7}{2} \lambda \] ### Step 2: Calculate the Path Difference Due to the Glass Sheet When a glass sheet of thickness \( T \) and refractive index \( \mu \) is placed in front of one of the slits, it introduces an additional path difference. The path difference \( \Delta x \) introduced by the glass sheet is given by: \[ \Delta x = (\mu - 1) T \] Here, the refractive index \( \mu \) of the glass sheet is 1.5. ### Step 3: Set Up the Equation We know that the path difference created by the glass sheet must equal the path difference for the 4th dark fringe: \[ (\mu - 1) T = \frac{7}{2} \lambda \] Substituting \( \mu = 1.5 \): \[ (1.5 - 1) T = \frac{7}{2} \lambda \] This simplifies to: \[ 0.5 T = \frac{7}{2} \lambda \] ### Step 4: Solve for Thickness \( T \) Now, we can solve for \( T \): \[ T = \frac{7 \lambda}{0.5} = 14 \lambda \] ### Step 5: Substitute the Wavelength The given wavelength \( \lambda \) is 6000 Å (angstroms). We need to convert this to meters for standard SI units: \[ \lambda = 6000 \, \text{Å} = 6000 \times 10^{-10} \, \text{m} = 6 \times 10^{-7} \, \text{m} \] Now substituting this value into the equation for \( T \): \[ T = 14 \times (6 \times 10^{-7} \, \text{m}) = 8.4 \times 10^{-6} \, \text{m} \] ### Step 6: Convert to Micrometers To express \( T \) in micrometers: \[ T = 8.4 \times 10^{-6} \, \text{m} = 8.4 \, \mu m \] ### Final Answer Thus, the thickness of the glass sheet is: \[ \boxed{8.4 \, \mu m} \]

To solve the problem step by step, we will follow the reasoning provided in the video transcript. ### Step 1: Understand the Shift of the Central Fringe The central fringe shifts to the position of the 4th dark fringe when a glass sheet is introduced. The path difference for the dark fringes is given by the formula: \[ \text{Path difference} = \left(n + \frac{1}{2}\right) \lambda \] where \( n \) is the order of the dark fringe. For the 4th dark fringe, \( n = 3 \): ...
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