Home
Class 12
PHYSICS
In YDSE if a slab whose refractive index...

In YDSE if a slab whose refractive index can be varied is placed in front of one of the slits. Then, the variation of resultant intensity at mid-point of screen with `mu` will be best represented by `(mu is greater than or equal to 1)

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
C
Shift = `((mu-1)tD)/d`
At `mu =1, shift=0`
` (##DCP_V05_C32_E01_065_S01.png" width="80%">
Therefore, intensity at centre is maximum or `I_0`.
As `mu` increases fringes shift upwards as shown in figure.
So, intensity at P first decreases to zero (as Q
reaches at P), then it further increases to `I_0`(as
point R reaches to P).
Promotional Banner

Topper's Solved these Questions

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise LEVEL 2 (single correct option)|1 Videos

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Level 2 More Than One Correct|6 Videos

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Subjective Questions|5 Videos

  • GRAVITATION

    DC PANDEY ENGLISH|Exercise All Questions|135 Videos

  • MAGNETIC FIELD AND FORCES

    DC PANDEY ENGLISH|Exercise Medical entrance s gallery|59 Videos

Similar Questions

Explore conceptually related problems

In a YDSE if a slab whose refractive index can be varied is palced in fron of one of the slits then the variation of resultant intensity of mid-point of screen with mu will be represented by (assume slits of equal width and there is no absorption by slab)

In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .

In YDSE , slab of thickness t and refractive index mu is placed in front of any slit. Then displacement of central maximu is terms of fringe width when light of wavelength lamda is incident on system is

Minimum thickness of a mica sheet having mu=(3)/(2) which should be placed in front of one of the slits in YDSE is required to reduce the intensity at the centre of screen to half of maximum intensity is

In young's double-slit experiment, both the slits produce equal intensities on a screen. A 100% transparent thin film of refractive index mu = 1.5 is kept in front of one of the slits, due to which the intensity at the point O on the screen becomes 75% of its initial value. If the wavelength of monochromatic light is 720 nm, then what is the minimum thickness (in nm) of the film?

The slits in a double-slit interference experiment are illuminated by orange light (lambda = 60 nm) . A thin transparent plastic of thickness t is placed in front of one of the slits. The nunber of fringes shifting on screen is plotted versus the refractive index mu of the plastic in graph shown in figure. The value of t is

In YDSE, both slits produce equal intensities on the screen. A 100% transparent thin film is placed in front of one of the slits. Now, the intensity on the centre becomes 75% of the previous intensity. The wavelength of light is 6000Å and refractive index of glass is 1.5. Thus, minimum thickness of the glass slab is

A monochromatic light of lambda=500 nm is incident on two identical slits separated by a distance of 5xx10^(-4)m . The interference pattern is seen on a screen placed at a distance of 1 m from the plane of slits. A thin glass plate of thickness 1.5xx10^(-6)m and refractive index mu=1.5 is placed between one of the slits and the screen. Find the intensity at the center of the screen if the intensity is I_(0) in the absence of the plate. Also find the lateral shift of the central maxima and number of fringes crossed through center.

A thin glass plate of thickness t and refractive index mu is inserted between screen and one of the slits in a young's experiment. If the intensity at the centre of the screen is I, what was the intensity at the same point prior to the introduction of the sheet.

In a YDSE experiment the two slits are covered with a transparent membrane of negligible thickness which allows light to pass through it but does not allow water. A glass slab of thickness t=0.41 mm and refractive index mu_(g)=1.5 is placed infront of one of the slits as shown in the figure. The separation between the slits is d=0.30 mm . The entire space to the left of the slits is filled with water of refractive index mu_(w)=4//3 . A coherent light of intensity I and absolute wavelength lambda=5000Å is being incident on the slits making an angle 30^(@) with horizontal. If screen is placed at a distance D=1m from the slits, find ( a ) the position of central maxima. ( b ) the intensity at point O .