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In a Zener regulated power supply a Zene...

In a Zener regulated power supply a Zener diode with `V_(Z) = 6.0` V is used for regulation. The load current is to be 4.0 mA and the unregulated input is 10.0 V. What should be the value of series resistor `R_(S)`?

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The correct Answer is:
A

Zener current ` I_z ` should be sufficiently larger than load current ` I_L`

Given ` I_L = 4.0 mA `
So. Let us take `I_z `to be five times `I_L ` or `I_Z = 20mA`
Total current `I = I_Z + I_L = 24.0mA `
Input voltage ` V_"in" = 10 V `
Zener diaode voltage ` V_Z = 6V `
`:. ` Voltage drop across resistance , ` V_R = V_"in" - V_Z `
` or `V_R = (10 - 6) V = 4V `
Now , ` R = V_R / I_R = 4 / (24 xx 10^(-3)) = 167 Omega`
The nearest value of carbon resistor is ` 150 Omega ` . So , a series resistor of ` 150 Omega ` is appropriate.
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