In an n-p-n transistor circuit , the collector currents is 10mA . If 95 per cent of the electrons emitted reach the collector, which of the following statements are true?

Options

A. (a) The emitter current will be 8 mA.
B. (b) the emitter current will be 10 .53 mA.
C. (c ) The base current will be 0.53 mA.
D. (d) The base current will be 2 mA.

Explanation

To solve the problem, we need to analyze the given information about the n-p-n transistor circuit and apply the relevant formulas.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Collector current, \( I_C = 10 \, \text{mA} \)
- Percentage of electrons reaching the collector = 95%

2. **Relate Emitter Current to Collector Current:**
- According to the problem, 95% of the emitter current reaches the collector. Therefore, we can express this relationship as:
\[ I_C = 0.95 \times I_E \]

3. **Rearranging the Equation to Find Emitter Current:**
- We can rearrange the equation to solve for the emitter current \( I_E \):
\[ I_E = \frac{I_C}{0.95} \]
- Substituting the value of \( I_C \):
\[ I_E = \frac{10 \, \text{mA}}{0.95} \approx 10.53 \, \text{mA} \]

4. **Calculate Base Current:**
- The relationship between emitter current, base current, and collector current in a transistor is given by:
\[ I_E = I_B + I_C \]
- Rearranging gives us:
\[ I_B = I_E - I_C \]
- Substituting the values we have:
\[ I_B = 10.53 \, \text{mA} - 10 \, \text{mA} = 0.53 \, \text{mA} \]

5. **Conclusion:**
- We have calculated:
- Emitter current \( I_E \approx 10.53 \, \text{mA} \)
- Base current \( I_B \approx 0.53 \, \text{mA} \)

6. **Evaluate the Statements:**
- Option 1: Emitter current is 8 mA → **False**
- Option 2: Emitter current is 10.53 mA → **True**
- Option 3: Base current is 0.53 mA → **True**
- Option 4: Base current is 2 mA → **False**

### Final Answer:
The true statements are:
- Option 2: The emitter current will be 10.53 mA.
- Option 3: The base current will be 0.53 mA.