Find the velocity of center of mass of the system shown in the figure.

Explanation

Here, `m_(1) = 1kg`, `v_(1) = 2i,`
`m_(2) = 2 kg`, `v_(2) = 2 cos 30^(@)i - 2 sin 30^(@)`
`v_(CM) = (m_(1)v_(1) + m_(2)v_(2))/(m_(1)+m_(2))`
`(1 xx 2i + 2(2 cos 30^(@)i - 2sin 30^(@)j))/(1+2)`
`v_(CM) = (2i + 2sqrt3i - 2j)/3 = ((2+2sqrt(3))/3 )i - 2/3j`