Two particles of mass `m_(1)` and `m_(2)` are projected from the top of a tower. The particle `m_(1)` is projected vertically downward with speed u and `m_(2)` is projected horizontally with same speed. Find acceleration of CM of system of particles by neglecting the effect of air resistance.

Explanation

To find the acceleration of the center of mass (CM) of the system of two particles projected from the top of a tower, we can follow these steps:

### Step 1: Identify the forces acting on the particles
Both particles \( m_1 \) and \( m_2 \) are subjected to gravitational force. The only force acting on them is the weight due to gravity, which acts downward.

### Step 2: Determine the acceleration of each particle
Since both particles are in free fall (neglecting air resistance), they will experience the same acceleration due to gravity, denoted as \( g \). Thus:
- The acceleration of particle \( m_1 \) (which is projected downward) is \( a_1 = g \) (downward).
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