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Three identicle particle each of mass `1 kg` are placed with their centres on a straight line. Their centres are marked `P, Q and R` respectively. The distance of centre of mass of the system from `P` is.

A

`(PQ + PR +QR)/(3)`

B

`(PQ + PR)/3`

C

`(PQ + QR)/3`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
B

`X_(CM)` (from P) `=(m xx O +m xx PQ + m xx PR)/(m+m+m)` (m = 1kg)

or `X_(CM) = (PQ + PR)/3`
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