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If the kinetic energy of a body increase...

If the kinetic energy of a body increases by `0.1 %` the percent increase of its momentum will be

A

(a) `0.05%`

B

(b) `0.1%`

C

(c) `1.0%`

D

(d) `10%`

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The correct Answer is:
To solve the problem, we need to find the percent increase in momentum when the kinetic energy of a body increases by 0.1%. Let's go through the steps systematically. ### Step 1: Define the initial kinetic energy Let the initial kinetic energy of the body be represented as \( K \). ### Step 2: Calculate the final kinetic energy The kinetic energy increases by 0.1%. Therefore, the final kinetic energy \( K' \) can be expressed as: \[ K' = K + 0.1\% \text{ of } K = K + \frac{0.1}{100} K = K \left(1 + \frac{0.1}{100}\right) = K \left(1 + 0.001\right) = K \times 1.001 \] ### Step 3: Express the initial momentum The momentum \( P_i \) of the body can be expressed in terms of kinetic energy: \[ P_i = \sqrt{2mK} \] where \( m \) is the mass of the body. ### Step 4: Express the final momentum Similarly, the final momentum \( P_f \) can be expressed as: \[ P_f = \sqrt{2mK'} = \sqrt{2m \left(K \times 1.001\right)} = \sqrt{2mK \times 1.001} = \sqrt{2mK} \sqrt{1.001} = P_i \sqrt{1.001} \] ### Step 5: Calculate the percent increase in momentum The percent increase in momentum can be calculated using the formula: \[ \text{Percent Increase} = \left(\frac{P_f - P_i}{P_i}\right) \times 100 \] Substituting \( P_f \): \[ \text{Percent Increase} = \left(\frac{P_i \sqrt{1.001} - P_i}{P_i}\right) \times 100 = \left(\sqrt{1.001} - 1\right) \times 100 \] ### Step 6: Approximate \( \sqrt{1.001} \) Using the binomial approximation for small values (since \( 0.001 \) is small): \[ \sqrt{1+x} \approx 1 + \frac{x}{2} \quad \text{for small } x \] Thus, for \( x = 0.001 \): \[ \sqrt{1.001} \approx 1 + \frac{0.001}{2} = 1 + 0.0005 = 1.0005 \] ### Step 7: Calculate the percent increase Now substituting back: \[ \text{Percent Increase} = \left(1.0005 - 1\right) \times 100 = 0.0005 \times 100 = 0.05\% \] ### Conclusion The percent increase in momentum when the kinetic energy increases by 0.1% is \( 0.05\% \). ### Final Answer Thus, the correct option is **A: 0.05%**. ---

To solve the problem, we need to find the percent increase in momentum when the kinetic energy of a body increases by 0.1%. Let's go through the steps systematically. ### Step 1: Define the initial kinetic energy Let the initial kinetic energy of the body be represented as \( K \). ### Step 2: Calculate the final kinetic energy The kinetic energy increases by 0.1%. Therefore, the final kinetic energy \( K' \) can be expressed as: \[ ...
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