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A bullet moving with a speed of 100 ms^(...

A bullet moving with a speed of `100 ms^(-1)` can just penetrate into two planks of equal thickness. Then the number of such planks, if speed is doubled will be .

A

4

B

8

C

6

D

10

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The correct Answer is:
To solve the problem step-by-step, we will analyze the motion of the bullet as it penetrates the planks and how the distance it travels relates to its speed. ### Step 1: Understand the Initial Conditions The bullet penetrates 2 planks of equal thickness at an initial speed of \(100 \, \text{m/s}\). Let the thickness of each plank be \(B\). Therefore, the total distance the bullet travels through the planks is \(2B\). ### Step 2: Use the Kinematic Equation We can use the kinematic equation for uniformly decelerated motion: \[ v^2 = u^2 - 2as \] where: - \(v\) is the final velocity (0, since the bullet stops), - \(u\) is the initial velocity (100 m/s), - \(a\) is the deceleration, - \(s\) is the distance traveled (which is \(2B\)). Rearranging the equation gives us: \[ 0 = (100)^2 - 2a(2B) \] This simplifies to: \[ 10000 = 4aB \] From this, we can express \(a\): \[ a = \frac{10000}{4B} = \frac{2500}{B} \] ### Step 3: Analyze the New Conditions Now, if the speed of the bullet is doubled, the new speed \(u' = 200 \, \text{m/s}\). We want to find out how many planks the bullet can penetrate at this new speed. ### Step 4: Apply the Kinematic Equation Again Using the same kinematic equation for the new speed: \[ v^2 = u'^2 - 2as' \] where \(s'\) is the new distance traveled. Setting \(v = 0\) gives us: \[ 0 = (200)^2 - 2a s' \] This simplifies to: \[ 40000 = 2a s' \] Substituting \(a = \frac{2500}{B}\) into the equation: \[ 40000 = 2 \left(\frac{2500}{B}\right) s' \] This simplifies to: \[ 40000 = \frac{5000 s'}{B} \] Rearranging gives: \[ s' = \frac{40000 B}{5000} = 8B \] ### Step 5: Calculate the Number of Planks Since each plank has a thickness \(B\), the number of planks \(N\) that can be penetrated is: \[ N = \frac{s'}{B} = \frac{8B}{B} = 8 \] ### Conclusion Thus, if the speed of the bullet is doubled, it can penetrate **8 planks**. ---

To solve the problem step-by-step, we will analyze the motion of the bullet as it penetrates the planks and how the distance it travels relates to its speed. ### Step 1: Understand the Initial Conditions The bullet penetrates 2 planks of equal thickness at an initial speed of \(100 \, \text{m/s}\). Let the thickness of each plank be \(B\). Therefore, the total distance the bullet travels through the planks is \(2B\). ### Step 2: Use the Kinematic Equation We can use the kinematic equation for uniformly decelerated motion: \[ ...
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