A ball of mass m is released from the to...

A ball of mass m is released from the top of an inclined plane of inclination `theta` as shown. It strikes a rigid surface at a distances `(3l)/(4)` from top elastically. Impulse to ball by the rigid surface is

`msqrt(3/2)gh`

`msqrt(3gh)`

`2msqrt(3gh)`

`msqrt(6gh)`

Text Solution

Verified by Experts

The correct Answer is:

Loss in PE = gain in KE
`mgh_(1) = 1/2mv^(2)`
`mg xx 3/4h = 1/2mv^(2) rArr v=sqrt(3gh)/2`
Now, impulse imparted, `J = 2mv = 2msqrt(3gh)/2` = `msqrt(6gh)`

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