From a circular disc of radius R a square is cut out with a radius as its diagonal . The distane of the centre of mass of the remainder from the centre of the disc is

Options

A. `R/(4pi-2)`
B. `R/(2pi)`
C. `R/(pi-2)`
D. `R/(2pi -2)`

Answer

A

Explanation

`A_(1)(CC_(1)) = A_(2)(CC_(2))`

side of square will be `R/sqrt(2)`
`therefore CC_(2) = A_(1)/A_(2)(CC_(1) = (R/sqrt(2))^(2)/(piR^(2) - (R//sqrt(2))^(2)(R/2) = (R)/(4pi-2)`