Two particles of masses `m_(1),m_(2)` move with initial velocities `u_(1)"and"u_(2)`. On collision, one of the particles get excited to higher level, after absorbing energy `epsi`. If final velocities of particles be `v_(1)" and"v_(2)`, then we must have

Options

A. `m_(1)^(2)u_(1) + m_(2)^(2)u_(2)-epsilon =- m_(1)^(2)v_(1) + m_(2)^(2)v_(2)`
B. `1/2 m_(1)u_(1)^(2) + 1/2m_(2)u_(2)^(2)=1/2m_(1)v_(1)^(2) + 1/2m_(2)v_(2)^(2) - epsilon`
C. `1/2 m_(1)u_(1)^(2)+1/2m_(2)u_(2)^(2)-epsilon=1/2m_(1)v_(1)^(2)+1/2m_(2)v_(2)^(2)`
D. `1/2m_(1)^(2)u_(1)^(2)+1/2m_(2)^(2)u_(2)^(2) + epsilon=1/2m_(1)^(2)v_(1)^(2)+1/2m_(2)^(2)v_(2)^(2)`

Answer

C

Explanation

Total initial energy =`1/2(m_(1)u_(1)^(2) + 1/2(m_(2)u_(2)^(2)` ltbr Sinc,e after collision one particle absorb energy `epsilon`.
`therefore` Total final energy = `1/2(m_(1)v_(1)^(2) + 1/2m_(2)(v_(1)^(2) + epsilon`
From conservation of energy
`1/2m_(1)u_(1)^(2) + 1/2m_(2)u_(2)^(2) = 1/2(m_(1)v_(1)^(2) + 1/2(m_(2)v_(2)^(2) + epsilon`
`rArr 1/2(m_(1)u_(1)^(2) + 1/2(m_(2)u_(2)^(2) -epsilon = 1/2m_(1)v_(1)^(2) + 1/2m_(2)v_(2)^(2)`