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A mass of 10 g moving horizontally with ...

A mass of 10 g moving horizontally with a velocity of `100 cm^(-1)` strikes a pendulum bob of mass 10g. Length of string is 50 cm. The two masses stick together. The maximum height reached by the stystm now is (Take, `g= 10 ms^(-2)`

A

Zero

B

1.25 cm

C

2.5 cm

D

5cm

Text Solution

Verified by Experts

The correct Answer is:
B
`mu=(m+m)v rArr v=u/2 = 1/2m//s`
n=v^(2)/(2g) = 1/(8g) xx10 = 5/4=1.25`
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