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A particle moves in a straight line wit...

A particle moves in a straight line with constant acceleration under a constant force F. Select the correct alternative(s).

A

Power developed by this force varies linearly with time

B

Power developed by this force varies parabolically with time

C

Power developed by this force varies linearly with displacement

D

Power developed by this force varies parabolically with displacement

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The correct Answer is:
To solve the problem, we need to analyze the motion of a particle moving in a straight line with constant acceleration under a constant force \( F \). We will derive the relationships between power, velocity, and displacement. ### Step-by-Step Solution: 1. **Understanding the Basics**: - A particle is moving with constant acceleration \( a \) under a constant force \( F \). - According to Newton's second law, \( F = ma \), where \( m \) is the mass of the particle. 2. **Power Definition**: - Power \( P \) is defined as the rate at which work is done or energy is transferred. Mathematically, it can be expressed as: \[ P = F \cdot v \] where \( v \) is the velocity of the particle. 3. **Velocity Expression**: - From the equations of motion, the velocity \( v \) of the particle at time \( t \) can be expressed as: \[ v = u + at \] where \( u \) is the initial velocity. 4. **Substituting Velocity into Power**: - Substituting the expression for \( v \) into the power equation gives: \[ P = F \cdot (u + at) \] - This shows that power is directly proportional to time \( t \) since \( F \) and \( u \) are constants. 5. **Displacement Expression**: - Another equation of motion relates displacement \( s \) to time: \[ s = ut + \frac{1}{2}at^2 \] 6. **Finding Power in Terms of Displacement**: - From the equation \( v^2 = u^2 + 2as \), we can express \( v \) in terms of displacement: \[ v = \sqrt{u^2 + 2as} \] - Substituting this into the power equation gives: \[ P = F \cdot \sqrt{u^2 + 2as} \] 7. **Analyzing Power with Displacement**: - As \( s \) increases, \( P \) will vary as the square root of \( s \). Therefore, we can say: \[ P^2 \propto s \] - This indicates that power varies parabolically with displacement \( s \). ### Conclusion: - The correct alternatives are: - Power developed by this force varies linearly with time. - Power developed by this force varies parabolically with displacement.
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DC PANDEY ENGLISH-WORK, POWER AND ENERGY-B More than One Option is Correct
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