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A particle is moving with speed v= 2t^(2...

A particle is moving with speed `v= 2t^(2)` on the circumference of a circle of radius R. Match the quantities given in Table-1 with corresponding results in Table-2
`{:(,"Table-1",,"Table-2"),("(A)","Magnitude to tangential acceleration of particle","(P)","decreases with time"),("(B)","Magnitude of centripetal acceleration of particle","(Q)","increases with time"),("(C)","Magnitude of angular speed of particle with respect to centre of circle","(R)","remains constant"),("(D)","Angle between the total acceleration and centripetal acceleration of partilce","(S)","depends upon the value of radius R"):}`

Text Solution

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The correct Answer is:
(A)Q,(B)QS,(C)QS,(D)PS
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