For a mirror linear magnification m comes out to `+2`. What conclusions can be drawn from this ?

Options

A. mirror is concave
B. mirror can be convex or concave but it can not be place
C. object lies between pole and focus
D. object lies between focus

Answer

To solve the problem regarding the linear magnification \( m = +2 \) for a mirror, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Magnification**:
The magnification \( m \) is defined as the ratio of the height of the image \( h' \) to the height of the object \( h \):
\[ m = \frac{h'}{h} \]
Given that \( m = +2 \), this means that the image is twice the height of the object.

2. **Interpreting the Sign of Magnification**:
The positive sign of the magnification indicates that the image is erect. In optics, a positive magnification suggests that the image maintains the same orientation as the object.

3. **Determining the Type of Mirror**:
- A concave mirror can produce both real and virtual images, while a convex mirror only produces virtual images that are diminished.
- Since the magnification is positive and greater than 1, we can conclude that the image is virtual and magnified. This is characteristic of a concave mirror when the object is placed between the mirror's focus and its pole.

4. **Locating the Object's Position**:
- For a concave mirror, when the object is placed between the pole (P) and the focus (F), the image formed is virtual, erect, and magnified.
- Therefore, we can conclude that the object must be located between the pole and the focus of the concave mirror.

5. **Final Conclusions**:
- The image is virtual and erect.
- The mirror is a concave mirror.
- The object is located between the pole and the focus of the mirror.

### Summary of Conclusions:
1. The image is virtual and erect.
2. The mirror is a concave mirror.
3. The object is located between the pole and the focus.