Home
Class 11
PHYSICS
A converging lens is used to form an ima...

A converging lens is used to form an image on a screen. When the upper half of the lens is covered by an opaque screen

A

half of the image will disappear

B

complete image will be formed

C

intensity of the image will increases

D

intensity of the image will decreases

Text Solution

Verified by Experts

The correct Answer is:
B, D
Promotional Banner

Topper's Solved these Questions

  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise C. comprehension type question|14 Videos

  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise Matrix matching type Q.|8 Videos

  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise A. Only one option is correct (JEE Advance)|73 Videos

  • PROPERTIES OF MATTER

    DC PANDEY ENGLISH|Exercise Integer|8 Videos

  • ROTATION

    DC PANDEY ENGLISH|Exercise (C) Chapter Exercises|39 Videos

Similar Questions

Explore conceptually related problems

A converging lens is used to obtain an image of an object placed in front of it. The inverted image is formed between F_(2)and2F_(2) of the lens. Draw a ray diagram to illustrate the formation of the image obtained.

A converging lens is used to obtain an image of an object placed in front of it. The inverted image is formed between F_(2)and2F_(2) of the lens. Where is the object placed ?

A convex lens forms an image of an object on a screen 30 cm from the lens. When the lens is moved 90 cm towards the object, then the image is again formed on the screen. Then, the focal length of the lens is

A convex lens forms an image of an object on a screen. The height of the image is 9 cm . The lens is now displaced until an image is again obtained on the screen. Then height of this image is 4 cm . The distance between the object and the screen is 90 cm.

The filament of lamp is 80 cm from a screen and a converging lens forms an image of it on a screen, magnified three times. Find the distance of the lens from the filament and the focal length of the lens.

An object is placed 12cm in front of a lens to form an image on a screen. The size of the image is twice that of the object. What is the distance between the object and the image?

A thin converging lens forms a real image of an object located far away from the lens. The image is formed at A at a distance 4x from the lens and height of the image is h. A thin diverging lens of focal length x is placed at B [PB = 2x] and a converging lens of focal length 2x is placed at C [PC = 3x] . The principal axes of all lenses coincide. Find the height of the final image formed.

A convex lens is used to obtain a magnified image of an object on a screen . The object is at a distance 10 m from the lens . If the magnification is 19. the focal length of the lens is

When an object is placed at the proper distance ot the left of a converging lens, the image is focused in a screen 30 cm to the right of lens. A dieverging lens is now placed 15 cm to the right of the converging lens and it is found that the screen must be moved 19.2cm farther to the right to obtain a sharp image. Find the focal length of the diverging lens.

An object O is placed in front of a convex lens such that the lens forms a sharp image on the screen. The distance between the object and screen is 10 cm. The lens is made of glass at refractive index mu_(g) = (3)/(2) . The surrounding medium is air with refractive index 1. The focal length of the lens, used in the above experiment, satisfies the condition given by

DC PANDEY ENGLISH-RAY OPTICS-B. More than one option is correct
  1. A point object is placed at 30 cm from a convex glass lens (mu(g) = (3...

    Text Solution

    |

  2. For a concave mirror of focal length f, image is 2 times larger. Then ...

    Text Solution

    |

  3. For a concave mirror

    Text Solution

    |

  4. Focal length of a lens in air is f. Refractive index of the lens is mu...

    Text Solution

    |

  5. For what position of an object, a concave mirror forms a real image e...

    Text Solution

    |

  6. Refractive index of an equilateral prism is sqrt(2).

    Text Solution

    |

  7. Write laws of refraction. Explain the same with the help of ray diagra...

    Text Solution

    |

  8. A ray of light of wavelength u(0) and frequency v(0) enters a glass sl...

    Text Solution

    |

  9. There are three optical media 1,2 and 3 with the refractive indices mu...

    Text Solution

    |

  10. Parallel rays of light are falling on convex sphere surface of radius ...

    Text Solution

    |

  11. For a mirror linear magnification m comes out to +2. What conclusions ...

    Text Solution

    |

  12. A convex lens made of glass (mu(g)=3//2) has focal length f in air. Th...

    Text Solution

    |

  13. A converging lens is used to form an image on a screen. When the upper...

    Text Solution

    |

  14. A ray of light travelling in a transparent medium falls on a surface s...

    Text Solution

    |

  15. A horizontal ray of light passes through a prism whose apex angle is 4...

    Text Solution

    |

  16. The image formed by a concave mirror is twice the size of the object. ...

    Text Solution

    |

  17. Two refracting media are separated by a spherical interface as shown i...

    Text Solution

    |

  18. A small air bubble is trapped inside a transparent cube of size 12 cm...

    Text Solution

    |

  19. A plane mirror placed at the origin has hat(i) as the normal vector to...

    Text Solution

    |

  20. A ray of light moving along a vector (3sqrt(2) hat(i)-3 hat(j)-3 hat(k...

    Text Solution

    |