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A wire of length l is bent in the form a...

A wire of length l is bent in the form a circular coil of some turns. A current I flows through the coil. The coil is placed in a uniform magnetic field B. The maximum torqur on the coil can be

A

`(iBl^(2))/(4pi)`

B

`(iBl^(2))/(pi)`

C

`(iBl^(2))/(2pi)`

D

`(2iBl^(2))/(pi)`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will derive the maximum torque on a circular coil of wire placed in a uniform magnetic field. ### Step 1: Understand the Problem We have a wire of length \( L \) that is bent into a circular coil with \( n \) turns. A current \( I \) flows through the coil, which is placed in a uniform magnetic field \( B \). We need to find the maximum torque \( \tau \) acting on this coil. ### Step 2: Relate Length of Wire to the Coil The total length of the wire is equal to the circumference of the coil multiplied by the number of turns: \[ L = n \cdot (2\pi r) \] where \( r \) is the radius of the coil. ### Step 3: Solve for Radius From the equation above, we can express the radius \( r \) in terms of \( L \) and \( n \): \[ r = \frac{L}{2\pi n} \] ### Step 4: Calculate the Area of the Coil The area \( A \) of the circular coil can be calculated using the formula for the area of a circle: \[ A = \pi r^2 \] Substituting \( r \) from the previous step: \[ A = \pi \left(\frac{L}{2\pi n}\right)^2 = \frac{L^2}{4\pi n^2} \] ### Step 5: Calculate the Magnetic Moment The magnetic moment \( m \) of the coil is given by: \[ m = n \cdot I \cdot A \] Substituting the expression for area \( A \): \[ m = n \cdot I \cdot \frac{L^2}{4\pi n^2} = \frac{I L^2}{4\pi n} \] ### Step 6: Calculate the Torque The torque \( \tau \) on the coil in a magnetic field is given by: \[ \tau = m \cdot B \cdot \sin(\theta) \] where \( \theta \) is the angle between the magnetic moment and the magnetic field. For maximum torque, \( \sin(\theta) = 1 \) (i.e., \( \theta = 90^\circ \)): \[ \tau_{\text{max}} = m \cdot B \] Substituting the expression for \( m \): \[ \tau_{\text{max}} = \left(\frac{I L^2}{4\pi n}\right) \cdot B \] ### Step 7: Maximize the Torque To maximize the torque, we need to minimize \( n \). The minimum value of \( n \) is 1 (i.e., a single turn): \[ \tau_{\text{max}} = \frac{I L^2}{4\pi} \cdot B \] ### Final Result Thus, the maximum torque on the coil is: \[ \tau_{\text{max}} = \frac{I L^2 B}{4\pi} \]
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