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Velocity of a charged particle can remai...

Velocity of a charged particle can remain unchanged. If

A

it is moving only in electric field

B

it is moving only in magnetic field

C

it is moving both in electric and magnetic fields

D

neither in electric nor in magnetic fields

Text Solution

AI Generated Solution

The correct Answer is:
To determine under what conditions the velocity of a charged particle can remain unchanged, let's analyze each of the given statements step by step. ### Step-by-Step Solution: 1. **Statement A: Moving in an Electric Field** - When a charged particle moves in an electric field, it experiences a force given by \( F = qE \), where \( q \) is the charge and \( E \) is the electric field strength. - This force causes the particle to accelerate according to Newton's second law, \( F = ma \). - Since there is a non-zero force acting on the particle, it will experience acceleration, which means its velocity will change. - **Conclusion**: This statement is **false**. 2. **Statement B: Moving in a Magnetic Field** - When a charged particle moves in a magnetic field, it experiences a magnetic force given by \( F = q(v \times B) \), where \( v \) is the velocity of the particle and \( B \) is the magnetic field. - The magnetic force acts perpendicular to both the velocity of the particle and the magnetic field direction. - Since the force is always perpendicular to the displacement, the work done by the magnetic force is zero (as work is calculated as \( W = F \cdot d \cos(\theta) \), and here \( \theta = 90^\circ \)). - Because no work is done, the kinetic energy remains constant, and hence the speed (magnitude of velocity) of the particle remains unchanged. - **Conclusion**: This statement is **true**. 3. **Statement C: Moving in Both Electric and Magnetic Fields** - If a charged particle is moving in both electric and magnetic fields, the forces due to these fields can act in such a way that they cancel each other out. - If the electric force \( F_E = qE \) and the magnetic force \( F_B = q(v \times B) \) are equal in magnitude and opposite in direction, the net force on the particle will be zero. - With no net force acting on the particle, it will not accelerate, and its velocity will remain unchanged. - **Conclusion**: This statement is **true**. 4. **Statement D: Neither in Electric nor in Magnetic Field** - If a charged particle is not in an electric or magnetic field, there are no forces acting on it. - According to Newton's first law of motion, an object in motion will remain in motion with the same velocity unless acted upon by a net external force. - Therefore, the velocity of the charged particle will remain unchanged. - **Conclusion**: This statement is **true**. ### Final Conclusion: - The statements that are true are **B, C, and D**. - The only statement that is false is **A**.
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