Magnetic force on a charged particle is given by `vec F_(m) = q(vec(v) xx vec(B))` and electrostatic force `vec F_(e) = q vec (E)`. A particle having charge q = 1C and mass 1 kg is released from rest at origin. There are electric and magnetic field given by `vec(E) = (10 hat(i)) N//C for x = 1.8 m` and `vec(B) = -(5 hat(k)) T` for `1.8 m le x le 2.4 m`
A screen is placed parallel to y-z plane at `x = 3 m`. Neglect gravity forces.
The speed with which the particle will collide the screen is

Options

A. `(1)/(5)(3+(pi)/(6)+(1)/(sqrt3))`
B. `(1)/(5)(6+(pi)/(3)+sqrt3)`
C. `(1)/(3)(5+(pi)/(6)+(1)/sqrt3)`
D. `(1)/(3)(6+(pi)/(18)+sqrt3)`

Answer

a