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The displacement of two identical partic...

The displacement of two identical particles executing SHM are represented by equations.
`x_(1) = 4sin(10t+pi/6)` and `x_(2)=5cosepsilont`
For what value of epsilon energy of both the particles is same?

A

16 unit

B

6 unit

C

4 unit

D

8 unit

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of epsilon for which the energy of both particles executing Simple Harmonic Motion (SHM) is the same, we can follow these steps: ### Step 1: Understand the energy of SHM The total energy (E) of a particle in SHM is given by the formula: \[ E = \frac{1}{2} k A^2 \] where \( k \) is the force constant and \( A \) is the amplitude of the motion. ### Step 2: Relate energy to angular frequency The force constant \( k \) can also be expressed in terms of mass \( m \) and angular frequency \( \omega \): \[ k = m \omega^2 \] Thus, the energy can be rewritten as: \[ E = \frac{1}{2} m \omega^2 A^2 \] ### Step 3: Set up the equations for both particles For the first particle: - Displacement: \( x_1 = 4 \sin(10t + \frac{\pi}{6}) \) - Amplitude \( A_1 = 4 \) - Angular frequency \( \omega_1 = 10 \) The energy of the first particle is: \[ E_1 = \frac{1}{2} m (10^2) (4^2) \] For the second particle: - Displacement: \( x_2 = 5 \cos(\epsilon t) \) - Amplitude \( A_2 = 5 \) - Angular frequency \( \omega_2 = \epsilon \) The energy of the second particle is: \[ E_2 = \frac{1}{2} m (\epsilon^2) (5^2) \] ### Step 4: Set the energies equal Since the energies of both particles are the same: \[ E_1 = E_2 \] This gives us: \[ \frac{1}{2} m (10^2) (4^2) = \frac{1}{2} m (\epsilon^2) (5^2) \] ### Step 5: Simplify the equation We can cancel \( \frac{1}{2} m \) from both sides (assuming \( m \neq 0 \)): \[ (10^2)(4^2) = \epsilon^2 (5^2) \] ### Step 6: Substitute and solve for epsilon Calculating the left side: \[ 100 \times 16 = 1600 \] Calculating the right side: \[ \epsilon^2 \times 25 \] Setting them equal gives: \[ 1600 = 25 \epsilon^2 \] Now, solving for \( \epsilon^2 \): \[ \epsilon^2 = \frac{1600}{25} = 64 \] Taking the square root: \[ \epsilon = 8 \] ### Final Answer The value of epsilon for which the energy of both particles is the same is: \[ \epsilon = 8 \] ---
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