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A body is executing simple harmonic moti...

A body is executing simple harmonic motion. At a displacement x (from its mean position) its potential energy is `E_(1)` and at a displacement y its potential energy is `E_(2)`. The potential energy is E at displacement (x+y) . Then:

A

`sqrt(E ) = sqrt(E_(1))-sqrt(E_(2))`

B

`sqrt(E ) = sqrt(E_(1))+sqrt(E_(2))`

C

`E = E_(1)-E_(2)`

D

`E=E_(1)+E_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the potential energies \(E_1\), \(E_2\), and \(E\) at different displacements in simple harmonic motion. ### Step-by-Step Solution: 1. **Understanding Potential Energy in SHM**: The potential energy \(E\) of a body executing simple harmonic motion (SHM) at a displacement \(x\) from the mean position is given by the formula: \[ E = \frac{1}{2} k x^2 \] where \(k\) is the spring constant. 2. **Expressing \(E_1\) and \(E_2\)**: - At displacement \(x\), the potential energy \(E_1\) can be expressed as: \[ E_1 = \frac{1}{2} k x^2 \] - At displacement \(y\), the potential energy \(E_2\) can be expressed as: \[ E_2 = \frac{1}{2} k y^2 \] 3. **Expressing Potential Energy at Displacement \(x + y\)**: - At displacement \(x + y\), the potential energy \(E\) can be expressed as: \[ E = \frac{1}{2} k (x + y)^2 \] 4. **Expanding the Expression for \(E\)**: - Expanding the square in the expression for \(E\): \[ E = \frac{1}{2} k (x^2 + 2xy + y^2) \] 5. **Relating \(E\), \(E_1\), and \(E_2\)**: - Substitute the expressions for \(E_1\) and \(E_2\): \[ E = E_1 + E_2 + kxy \] - Rearranging gives: \[ kxy = E - E_1 - E_2 \] 6. **Finding the Relationship**: - We can express \(x\) and \(y\) in terms of \(E_1\) and \(E_2\): \[ x = \sqrt{\frac{2E_1}{k}}, \quad y = \sqrt{\frac{2E_2}{k}} \] - Thus, substituting these values into the equation for \(E\): \[ E = \frac{1}{2} k \left(\sqrt{\frac{2E_1}{k}} + \sqrt{\frac{2E_2}{k}}\right)^2 \] 7. **Final Relationship**: - After simplification, we find: \[ \sqrt{E} = \sqrt{E_1} + \sqrt{E_2} \] ### Conclusion: The relationship between the potential energies is: \[ \sqrt{E} = \sqrt{E_1} + \sqrt{E_2} \] Thus, the correct answer is option number 2.
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