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An aeroplane moving horizontally with a speed of `720 km//h` drops a food pocket, while flying at a height of 396.9 m . the time taken by a food pocket to reach the ground and its horizontal range is (Take `g = 9.8 m//sec`)

A

3s and 2000m

B

5s and 500 m

C

8s and 1500m

D

9s and 1800 m

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The correct Answer is:
To solve the problem, we need to find two things: the time taken by the food packet to reach the ground and its horizontal range. ### Step 1: Calculate the time taken to reach the ground We can use the formula for the distance fallen under gravity: \[ s = ut + \frac{1}{2} g t^2 \] Where: - \( s \) is the distance fallen (396.9 m), - \( u \) is the initial velocity (0 m/s, since the packet is dropped), - \( g \) is the acceleration due to gravity (9.8 m/s²), - \( t \) is the time taken to fall. Since the initial velocity \( u = 0 \), the equation simplifies to: \[ s = \frac{1}{2} g t^2 \] Substituting the known values: \[ 396.9 = \frac{1}{2} \times 9.8 \times t^2 \] ### Step 2: Rearranging the equation To isolate \( t^2 \), we multiply both sides by 2: \[ 2 \times 396.9 = 9.8 \times t^2 \] This simplifies to: \[ 793.8 = 9.8 \times t^2 \] Now, divide both sides by 9.8: \[ t^2 = \frac{793.8}{9.8} \] ### Step 3: Calculate \( t^2 \) Calculating the right side: \[ t^2 = 81 \] ### Step 4: Calculate \( t \) Taking the square root of both sides gives: \[ t = \sqrt{81} = 9 \text{ seconds} \] ### Step 5: Calculate the horizontal range The horizontal range \( R \) can be calculated using the formula: \[ R = u_x \times t \] Where: - \( u_x \) is the horizontal speed of the airplane, - \( t \) is the time of flight. The speed of the airplane is given as 720 km/h. We need to convert this to meters per second: \[ u_x = 720 \text{ km/h} = \frac{720 \times 1000}{3600} = 200 \text{ m/s} \] ### Step 6: Calculate the horizontal range Now substituting the values into the range formula: \[ R = 200 \text{ m/s} \times 9 \text{ s} \] Calculating this gives: \[ R = 1800 \text{ m} \] ### Final Results - Time taken by the food packet to reach the ground: **9 seconds** - Horizontal range of the food packet: **1800 meters** ---

To solve the problem, we need to find two things: the time taken by the food packet to reach the ground and its horizontal range. ### Step 1: Calculate the time taken to reach the ground We can use the formula for the distance fallen under gravity: \[ s = ut + \frac{1}{2} g t^2 \] ...
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