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A particle moves along a parabolic path ...

A particle moves along a parabolic path `y=-9x^(2)` in such a way that the `x` component of velocity remains constant and has a value `1/3m//s`. Find the instantaneous acceleration of the projectile (in `m//s^(2)`)

A

`(1)/(3) ms^(-2)`

B

`3 ms^(-2)`

C

`(2)/(3) ms^(-2)`

D

`2ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Comparing with the trajectory of projectile in which particle is projected from certain height horizontally `(theta = 0^(@))`
`y = x tan theta - (gx^(2))/(2u^(2)cos theta)`
Putting `theta = 0^(@)` and `g = a = 18 u^(2) = 2 ms^(-2)`
`( :' y=- 9x^(2), u =(1)/(3) ms^(-1))`
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