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The maximum range of a projectile is 500...

The maximum range of a projectile is 500m. If the particle is thrown up a plane, which is inclined at an angle of `30^@` with the same speed, the distance covered by it along the inclined plane will be

A

250m

B

500m

C

750m

D

1000m

Text Solution

Verified by Experts

The correct Answer is:
B
`(u^(2))/(g) = R_(max) = 500`
Now, `s = (u^(2))/(2a) = (u^(2))/(2g sin 30^(@)) = (u^(2))/(g) = 500 m`
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