Assertion Particle-1 is dropped from a tower and particle-2 is projected horizontal from the same tower. Then both the particles reach the ground simultaneously.
Reason Both are particles strike the ground with different speeds.

Options

A. If both Asseration and Reason are correct and Reason is the correct explanation of Assertion
B. If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion
C. If Assertion is true but Reason is false
D. If Assertion is false but Reason is true

Explanation

To solve the question, we need to analyze both the assertion and the reason provided.

### Step-by-Step Solution:

1. **Understanding the Scenario**:
- Particle-1 is dropped from a tower (initial velocity, \( u_1 = 0 \)).
- Particle-2 is projected horizontally from the same height (initial vertical velocity, \( u_2 = 0 \) in the vertical direction, but has a horizontal component).

2. **Time of Flight Calculation**:
- Both particles fall from the same height \( h \).
- The time of flight \( t \) for both particles can be calculated using the formula for free fall:
\[ h = \frac{1}{2} g t^2 \]
- Rearranging gives:
\[ t = \sqrt{\frac{2h}{g}} \]
- Since both particles are falling from the same height, they will have the same time of flight, \( t \).

3. **Final Velocity Calculation**:
- For Particle-1 (dropped):
- The final vertical velocity \( v_1 \) can be calculated using:
\[ v_1 = u_1 + gt = 0 + gt = gt \]
- For Particle-2 (projected horizontally):
- The final vertical velocity \( v_2 \) is also given by:
\[ v_2 = u_2 + gt = 0 + gt = gt \]
- However, Particle-2 also has a horizontal velocity component \( u_0 \), which does not affect the time of flight but contributes to its overall speed.

4. **Conclusion on Speeds**:
- The speed of Particle-1 when it hits the ground is \( v_1 = gt \).
- The speed of Particle-2 when it hits the ground has both vertical and horizontal components. The vertical component is \( gt \) and the horizontal component is \( u_0 \). Thus, its resultant speed can be calculated using Pythagorean theorem:
\[ v_2 = \sqrt{(u_0)^2 + (gt)^2} \]
- Since \( u_0 \) is not zero, \( v_2 \) will be greater than \( v_1 \).

5. **Final Assessment**:
- **Assertion**: Both particles reach the ground simultaneously - **True**.
- **Reason**: Both particles strike the ground with different speeds - **True**.
- However, the reason does not correctly explain the assertion, as the assertion is based on the same height and time of flight, not the difference in speed.

### Final Answer:
- The assertion is true, and the reason is also true, but the reason is not the correct explanation of the assertion.