A particle of mass m is executing uniform circular motion on a path of radius r. If p is the magnitude of its linear momentum. The radial force acting on the paritcles is

Options

A. `(L^(2))/(mr)`
B. `(L^(2))/(mr^(2))`
C. `(L^(2))/(mr^(3))`
D. `(L)/(mr^(2))`

Answer

C

Explanation

`L=mvr thereforev=(L)/(mr)`
`F=(mv^(2))/(r)=(L^(2))/(mr^(3))`