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A motor cyclist moving with a velosity o...

A motor cyclist moving with a velosity of `72 km h^(-1)` on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20km. The acceleration due to gravity is `10 ms^(-2)`. IN order to avoid skidding , he must not bend with respesct to the vertical plane by an angle greater then

A

`theta=tan^(-1)(4)`

B

`theta=45^(@)`

C

`theta=tan^(-1)(2)`

D

`theta=tan^(-1)(6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v=144kmh^(-1)=144xx(5)/(18)ms^(-1)=40ms^(-1)`
`tantheta=(v^(2))/(Rg)`
`rArr" "tantheta=((40)^(2))/(40xx10)=(1600)/(400)=4`
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DC PANDEY ENGLISH-CIRCULAR MOTION-Taking it together
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