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As shown in the figure, a disc of mass m...

As shown in the figure, a disc of mass `m` is rolling without slipping a angular velocity `omega`. When it crosses point `B` disc will be in `:`

A

zero

B

`Romegasin((theta)/(2))`

C

`2Romegasin((theta)/(2))`

D

`sqrt3Romegasin((theta)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`|v_(AB)|=|v_(A)-v_(B)|=sqrt((Romega)^(2)+(Romega)^(2)-2(Romega)(Romega)costheta)`
`=2Romegasin.(theta)/(2)`
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