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Three particles A, B and C move in a cir...

Three particles A, B and C move in a circle of radius `r=(1)/(pi)`m, in anti-clockwise direaction with speed `1ms^(-1), 2.5ms^(-1)` and `2ms^(-1)` respectively. The initial position of A, B and C are as shown in figure.

The ratio of distance travelled by B and C by the instant A, B and C meet for the first time is

A

`3:2`

B

`5:4`

C

`3:5`

D

`3:7`

Text Solution

Verified by Experts

The correct Answer is:
B
`(d_(B))/(d_(C))=(v_(B^(t)))/(v_(C^(t)))=(v_(B))/(c_(C))=(2.5)/(2)=(5)/(4)`
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