Three identical particles are joined together by a thread as shown in figure All the partical are moving in a horizontal plane If the vertical of the outermost particle is `v_(0)` then the ratio of tension in the three sections of the string `(T_(1):T_(2):T_(3) = ?)` is

Options

A. `3:5:7`
B. `3:4:5`
C. `7:11:6`
D. `3:5:6`

Answer

D

Explanation

Let `omega` is the angular speed of revolution.

`T_(3)=momega^(3)(3l)`
`T_(2)-T_(3)=momega^(2)2lrArrT_(2)=momega^(2)(5l)`
`T_(1)-T_(2)=momega^(2)lrArrT_(1)=momega^(2)(6l)`
`T_(3):T_(2):T_(1)=3:5:6`