A satellite of time period 2A h is orbiting the earth at a height 6R above the surface of earth, where R is radius of earth. What will be the time period of another satellite at a height 2.5 R from the surface of earth ?

Explanation

To solve the problem, we will use Kepler's third law of planetary motion, which states that the square of the time period (T) of a satellite is directly proportional to the cube of the semi-major axis (r) of its orbit. The relationship can be expressed as:

\[ T^2 \propto r^3 \]

### Step-by-Step Solution:

1. **Identify the Given Data:**
- The time period of the first satellite (T1) = 2A hours.
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