At a point above the surface of the earth, the gravitational potential is `-5.12 xx 10^(7)` J/kg and the acceleration due to gravity is `6.4 m//s^(2)`. Assuming the mean radius of the earth to be 6400 km, calculate the height of the point above the earth's surface.

Explanation

To solve the problem, we need to find the height of a point above the Earth's surface where the gravitational potential and acceleration due to gravity are given.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Gravitational potential (V) = \(-5.12 \times 10^7 \, \text{J/kg}\)
- Acceleration due to gravity (g) = \(6.4 \, \text{m/s}^2\)
- Mean radius of the Earth (R) = \(6400 \, \text{km} = 6400 \times 10^3 \, \text{m}\)
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