Home
Class 11
PHYSICS
Calculate the escape velocity from the s...

Calculate the escape velocity from the surface of a planet of mass `14.8 xx 10^(22)` kg. It is given that radius of the planet is `3.48 xx 10^(6)` m.

Text Solution

AI Generated Solution

To calculate the escape velocity from the surface of a planet, we can use the formula: \[ V_e = \sqrt{\frac{2 G M_p}{R_p}} \] where: - \( V_e \) is the escape velocity, ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    DC PANDEY ENGLISH|Exercise Solved Examples|16 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise Miscellaneous Examples|8 Videos
  • GENERAL PHYSICS

    DC PANDEY ENGLISH|Exercise INTEGER_TYPE|2 Videos
  • KINEMATICS

    DC PANDEY ENGLISH|Exercise INTEGER_TYPE|10 Videos

Similar Questions

Explore conceptually related problems

Find the escape velocity of a body from the surface of Mars. Assume it as a uniform sphere of mass 6.42 xx 10^(23) kg and radius 3.375 xx 10^(6) m .

Calculate the escape velocity from the moon. The mass of the moon =7.4xx10^22kg and radius of the moon =1740km

Calculate the escape velocity from the moon. The mass of the moon =7.4xx10^22kg and radius of the moon =1740km

What would be the escape velocity from the moon, it the mass of the moon is 7.4 xx 10^(22) kg and its radius is 1740 km ?

Calculate the escape speed on the surface of a planet of mass 7.5xx10^(25)g , and radius 1.6xx10^(8)cm. G=6.67xx10^(-8)"dyne"cm^(2)g^(-2) .

What will be the escape speed from a planet of mass 6xx10^(16) kg and radius 3.6xx10^(4) m ?

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

A satellite revolve round a planet in an orbit just above the surface of a planet. Taking G = 6.67 xx 10^(-11) Nm^(2) kg^(2) and mean density of the planet 5.51 xx 10^(3) kg//m^(3) find the period of the planet.

Calculate the gravitational intensity on the surface of Mars assuming it to be a uniform sphere. Given mass of Mars is 6.420 xx 10^(23) kg , its radius is 3.375 xx 10^(6) m .

Find the ratio of escape velocities from the earth and the moon. (Mass of the earth = 6.0 xx 10^(24) kg , Radius of the earth = 6400 km, Mass of the moon = 7.4 xx 10^(22) kg Radius of the moon = 1740 km.)

DC PANDEY ENGLISH-GRAVITATION-(C) Chapter Exercises
  1. Calculate the escape velocity from the surface of a planet of mass 14....

    Text Solution

    |

  2. Starting from the centre of the earth having radius R, the variation o...

    Text Solution

    |

  3. A satellite of mass m is orbiting the earth (of radius R) at a height ...

    Text Solution

    |

  4. At what height from the surface of earth the gravitation potential and...

    Text Solution

    |

  5. The ratio of escape velocity at earth (V(e)) to the escape velocity at...

    Text Solution

    |

  6. Kepler's third law states that square of period of revolution (T) of a...

    Text Solution

    |

  7. The reading of a spring balance corresponds to 100 N while situated at...

    Text Solution

    |

  8. The gravitational field due to an uniform solid sphere of mass M and r...

    Text Solution

    |

  9. What would be the value of acceleration due to gravity at a point 5 km...

    Text Solution

    |

  10. Two particles of equal mass m go round a circle of radius R under the ...

    Text Solution

    |

  11. What would be the escape velocity from the moon, it the mass of the mo...

    Text Solution

    |

  12. Two spheres of masses 16 kg and 4 kg are separated by a distance 30 m ...

    Text Solution

    |

  13. Orbital velocity of an artificial satellite does not depend upon

    Text Solution

    |

  14. Gravitational potential energy of body of mass m at a height of h abov...

    Text Solution

    |

  15. According to Kepler's law of planetary motion, if T represents time pe...

    Text Solution

    |

  16. If mass of a body is M on the earth surface, then the mass of the same...

    Text Solution

    |

  17. Two spherical bodies of masses m and 5m and radii R and 2R respectivel...

    Text Solution

    |

  18. The force of gravitation is

    Text Solution

    |

  19. Dependence of intensity of gravitational field (E) of earth with dista...

    Text Solution

    |

  20. Keeping the mass of the earth as constant, if its radius is reduced to...

    Text Solution

    |

  21. A body of mass m is raised to a height 10 R from the surface of the ea...

    Text Solution

    |