A body is projected upwards with a velocity of `4 xx 11.2 "km s"^(-1)` from the surface of earth.What will be the velocity of the body when it escapes from the gravitational pull of earth ?

Explanation

To solve the problem of a body projected upwards with a velocity of \(4 \times 11.2 \, \text{km/s}\) and to find the velocity of the body when it escapes from the gravitational pull of the Earth, we can follow these steps:

### Step 1: Calculate the initial velocity
The initial velocity \(v_0\) of the body is given as:
\[ v_0 = 4 \times 11.2 \, \text{km/s} = 44.8 \, \text{km/s} \]

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