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Figure shows two shells of masses m1 an...

Figure shows two shells of masses `m_1` and `m_2` . The shells are concentric. At which point, a particle of mass m shall experience zero force?

A

`(G(M_(1)+M_(2)))/(y^(2)),(G(M_(1)+M_(2)))/(y^(2))`

B

`(G(M_(1)+M_(2)+M_(3)))/(Y^(2)),(G(M_(1)+M_(2)))/(x^(2))`

C

`(G(M_(1)+M_(2)+M_(3)))/(a^(2)),(GM_(1))/(a^(2))`

D

`(G(M_(1)+M_(2)+M_(3)))/(C^(2)),(GM_(2))/(b^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
Gravitational field at an external point due to spherical shell of mass M is `((GM)/(r^(2)))` while at an internal point is zero
(i) Point Q is external to shell, `M_(1),M_(2) and M_(3)` So, field at Q will be
`E_(Q)=(GM_(1))/(y^(2))+(GM_(2))/(y^(2))+(GM_(3))/(y^(2))=(G)/(y^(2))(M_(1)+M_(2)+M_(3))`
(ii) Field at P will be
`F_(p)=(GM_(1))/(x^(2))+(GM_(2))/(x^(2))+0=(G)/(x^(2))(M_(1)+M_(2))`.
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