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Find the potential energy of 4-particles...

Find the potential energy of 4-particles, each of mass 1 kg placed at the four vertices of a square of side length 1 m.

A

`+4.0 G`

B

`7.5 G`

C

`-5.4 G`

D

`+6.3 G`

Text Solution

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To find the potential energy of four particles, each of mass 1 kg, placed at the vertices of a square with a side length of 1 m, we can follow these steps: ### Step 1: Understand the Configuration We have four particles, each of mass \( m = 1 \, \text{kg} \), located at the vertices of a square. Let's label the vertices as A, B, C, and D. The distance between adjacent vertices (e.g., A and B) is the side length of the square, which is \( 1 \, \text{m} \). ### Step 2: Calculate the Distances The distances between the particles are as follows: - Distance between adjacent vertices (e.g., A and B): \( r_{AB} = 1 \, \text{m} \) - Distance between opposite vertices (e.g., A and C): \( r_{AC} = \sqrt{2} \, \text{m} \) (using Pythagorean theorem) ### Step 3: Write the Formula for Gravitational Potential Energy The gravitational potential energy \( U \) between two masses \( m_1 \) and \( m_2 \) separated by a distance \( r \) is given by: \[ U = -\frac{G m_1 m_2}{r} \] where \( G \) is the gravitational constant, \( G \approx 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \). ### Step 4: Calculate the Potential Energy Between Each Pair of Particles We need to consider the potential energy between each pair of particles: 1. Between A and B: \[ U_{AB} = -\frac{G \cdot 1 \cdot 1}{1} = -G \] 2. Between B and C: \[ U_{BC} = -\frac{G \cdot 1 \cdot 1}{1} = -G \] 3. Between C and D: \[ U_{CD} = -\frac{G \cdot 1 \cdot 1}{1} = -G \] 4. Between D and A: \[ U_{DA} = -\frac{G \cdot 1 \cdot 1}{1} = -G \] 5. Between A and C: \[ U_{AC} = -\frac{G \cdot 1 \cdot 1}{\sqrt{2}} = -\frac{G}{\sqrt{2}} \] 6. Between B and D: \[ U_{BD} = -\frac{G \cdot 1 \cdot 1}{\sqrt{2}} = -\frac{G}{\sqrt{2}} \] ### Step 5: Sum the Potential Energies Now, we sum all the potential energies: \[ U_{\text{total}} = U_{AB} + U_{BC} + U_{CD} + U_{DA} + U_{AC} + U_{BD} \] Substituting the values: \[ U_{\text{total}} = -G - G - G - G - \frac{G}{\sqrt{2}} - \frac{G}{\sqrt{2}} \] \[ U_{\text{total}} = -4G - 2\frac{G}{\sqrt{2}} = -4G - \sqrt{2}G \] ### Step 6: Final Expression Thus, the total gravitational potential energy of the system is: \[ U_{\text{total}} = -\left(4 + \sqrt{2}\right)G \]

To find the potential energy of four particles, each of mass 1 kg, placed at the vertices of a square with a side length of 1 m, we can follow these steps: ### Step 1: Understand the Configuration We have four particles, each of mass \( m = 1 \, \text{kg} \), located at the vertices of a square. Let's label the vertices as A, B, C, and D. The distance between adjacent vertices (e.g., A and B) is the side length of the square, which is \( 1 \, \text{m} \). ### Step 2: Calculate the Distances The distances between the particles are as follows: - Distance between adjacent vertices (e.g., A and B): \( r_{AB} = 1 \, \text{m} \) ...
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