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The kinetic energy needed to project a b...

The kinetic energy needed to project a body of mass `m` from the earth surface (radius R) to infinity is

A

`(mgR)/(2)`

B

`2mgR`

C

`mgR`

D

`(mgR)/(2)`

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The correct Answer is:
To find the kinetic energy needed to project a body of mass \( m \) from the Earth's surface (radius \( R \)) to infinity, we can follow these steps: ### Step 1: Understand Escape Velocity The escape velocity (\( v_e \)) is the minimum velocity required for an object to break free from the gravitational attraction of a celestial body without any further propulsion. The formula for escape velocity from the surface of the Earth is given by: \[ v_e = \sqrt{2gR} \] where: - \( g \) is the acceleration due to gravity at the Earth's surface, - \( R \) is the radius of the Earth. ### Step 2: Calculate Kinetic Energy The kinetic energy (\( KE \)) required to project the body to infinity is given by the formula: \[ KE = \frac{1}{2} mv_e^2 \] Substituting the expression for escape velocity into this equation: \[ KE = \frac{1}{2} m (\sqrt{2gR})^2 \] ### Step 3: Simplify the Expression Now, simplify the expression: \[ KE = \frac{1}{2} m (2gR) \] This simplifies to: \[ KE = mgR \] ### Final Answer Thus, the kinetic energy needed to project a body of mass \( m \) from the Earth's surface to infinity is: \[ KE = mgR \]

To find the kinetic energy needed to project a body of mass \( m \) from the Earth's surface (radius \( R \)) to infinity, we can follow these steps: ### Step 1: Understand Escape Velocity The escape velocity (\( v_e \)) is the minimum velocity required for an object to break free from the gravitational attraction of a celestial body without any further propulsion. The formula for escape velocity from the surface of the Earth is given by: \[ v_e = \sqrt{2gR} \] ...
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DC PANDEY ENGLISH-GRAVITATION-Check Point 10.5
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