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Earth orbiting satellite will escape if...

Earth orbiting satellite will escape if

A

its speed is increased by 41 %

B

its KE is doubled

C

Both (a) and (b) are correct

D

Both (a) and (b) are wrong

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To determine the conditions under which an Earth-orbiting satellite will escape from its orbit, we need to understand the concepts of escape velocity and orbital velocity. ### Step-by-Step Solution: 1. **Understanding Orbital Velocity**: The orbital velocity (\(v_o\)) of a satellite is the speed required to maintain a stable orbit around the Earth. It is given by the formula: \[ v_o = \sqrt{\frac{GM}{R}} \] where \(G\) is the gravitational constant, \(M\) is the mass of the Earth, and \(R\) is the distance from the center of the Earth to the satellite. 2. **Understanding Escape Velocity**: The escape velocity (\(v_e\)) is the minimum speed needed for an object to break free from the gravitational attraction of a celestial body without any additional propulsion. It is given by: \[ v_e = \sqrt{2GM/R} \] This means that the escape velocity is \( \sqrt{2} \) times the orbital velocity: \[ v_e = \sqrt{2} \cdot v_o \] 3. **Condition for Escape**: For a satellite to escape the gravitational pull of the Earth, its velocity must be equal to or greater than the escape velocity. This can be expressed as: \[ v \geq v_e \] where \(v\) is the current velocity of the satellite. 4. **Increasing Orbital Velocity**: To escape, the satellite must increase its orbital velocity. The increase required to reach escape velocity can be calculated as: \[ \Delta v = v_e - v_o = \sqrt{2} \cdot v_o - v_o = ( \sqrt{2} - 1 ) \cdot v_o \] This implies that the satellite's speed must be increased by approximately 41% (since \( \sqrt{2} \approx 1.414 \)). 5. **Kinetic Energy Consideration**: The kinetic energy (\(KE\)) of the satellite is given by: \[ KE = \frac{1}{2} mv^2 \] If the velocity increases to escape velocity, the kinetic energy will increase by a factor of 2, since: \[ KE_{escape} = \frac{1}{2} m v_e^2 = \frac{1}{2} m (2 v_o^2) = 2 \cdot KE_{orbital} \] 6. **Conclusion**: Therefore, an Earth-orbiting satellite will escape if its speed is increased by 41% (to reach escape velocity) and this will result in the kinetic energy increasing by a factor of 2. ### Final Answer: An Earth-orbiting satellite will escape if its speed is increased by approximately 41% to reach escape velocity, resulting in a doubling of its kinetic energy.

To determine the conditions under which an Earth-orbiting satellite will escape from its orbit, we need to understand the concepts of escape velocity and orbital velocity. ### Step-by-Step Solution: 1. **Understanding Orbital Velocity**: The orbital velocity (\(v_o\)) of a satellite is the speed required to maintain a stable orbit around the Earth. It is given by the formula: \[ v_o = \sqrt{\frac{GM}{R}} ...
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