Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

Options

A. `v=sqrt((Gm)/(R))`
B. `v=sqrt((Gm)/(2R))`
C. `v=(1)/(2)sqrt((Gm)/(R))`
D. `v=sqrt((4Gm)/(R))`

Answer

C

Explanation

As gravitational force provides the centripetal force to the satellite to revolve around the earth

`(G.m.m)/(4R^(2))=(mv^(2))/((R))rArrv=(1)/(2)sqrt((Gm)/(R))`