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A satellite is moving in a circular orbi...

A satellite is moving in a circular orbit round the earth with a diameter of orbit 2R. At a certain point a rocket fixed to the satellite is fired such that it increases the velocity of the satellite tangentially. The resulting orbit of the satellite would be

A

same as before

B

circular orbit with diameter greater than 2R

C

elliptical orbit with minimum distance from the earth equal to R

D

elliptical orbit with maximum distance from the earth equal to R.

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The correct Answer is:
To solve the problem, we need to analyze the situation of a satellite moving in a circular orbit around the Earth and how its orbit changes when its velocity is increased tangentially. ### Step-by-Step Solution: 1. **Understanding the Initial Orbit:** - The satellite is initially in a circular orbit with a diameter of \(2R\). Therefore, the radius \(r\) of the orbit is: \[ r = \frac{2R}{2} = R \] 2. **Calculating Initial Velocity:** - The velocity \(V\) of a satellite in a circular orbit is given by the formula: \[ V = \sqrt{\frac{GM}{r}} \] - Substituting \(r = R\): \[ V = \sqrt{\frac{GM}{R}} \] 3. **Effect of Firing the Rocket:** - When the rocket is fired, it increases the satellite's tangential velocity. Let’s denote the new velocity as \(V'\), where: \[ V' > V \] - This means that the new velocity is greater than the orbital velocity required for a circular orbit. 4. **Determining the New Orbit:** - When the satellite's velocity exceeds the circular orbital velocity, it will no longer follow a circular path. Instead, it will enter an elliptical orbit. - The point at which the rocket is fired becomes the perigee (the closest point to Earth) of the new elliptical orbit. 5. **Finding the Minimum Distance to Earth:** - In an elliptical orbit, the minimum distance from the Earth (perigee) will be equal to the radius of the original circular orbit, which is \(R\). - Therefore, the resulting orbit of the satellite will be elliptical with the minimum distance from the Earth equal to \(R\). ### Conclusion: The resulting orbit of the satellite after the rocket is fired will be an elliptical orbit with a minimum distance from the Earth equal to \(R\). ### Final Answer: The resulting orbit of the satellite would be **an elliptical orbit with minimum distance from the Earth equal to \(R\)**. ---

To solve the problem, we need to analyze the situation of a satellite moving in a circular orbit around the Earth and how its orbit changes when its velocity is increased tangentially. ### Step-by-Step Solution: 1. **Understanding the Initial Orbit:** - The satellite is initially in a circular orbit with a diameter of \(2R\). Therefore, the radius \(r\) of the orbit is: \[ r = \frac{2R}{2} = R ...
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