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Energy of a satellite in circular orbit ...

Energy of a satellite in circular orbit is `E_(0)`. The energy required to move the satellite to a circular orbit of 3 times the radius of the initial orbit is

A

`(2)/(3)E_(0)`

B

`2E_(0)`

C

`(E_(0))/(3)`

D

`(3)/(2)E_(0)`

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The correct Answer is:
To solve the problem, we need to determine the energy required to move a satellite from its initial circular orbit to a new circular orbit that is three times the radius of the initial orbit. ### Step-by-Step Solution: 1. **Understanding the Energy of a Satellite in Orbit**: The total mechanical energy \( E \) of a satellite in a circular orbit is given by the formula: \[ E = -\frac{GMm}{2r} \] where \( G \) is the gravitational constant, \( M \) is the mass of the planet, \( m \) is the mass of the satellite, and \( r \) is the radius of the orbit. 2. **Initial Energy \( E_0 \)**: Let the initial radius of the orbit be \( r \). Therefore, the energy of the satellite in the initial orbit is: \[ E_0 = -\frac{GMm}{2r} \] 3. **Final Energy in the New Orbit**: The new orbit has a radius of \( 3r \). The energy of the satellite in this new orbit is: \[ E_{\text{final}} = -\frac{GMm}{2(3r)} = -\frac{GMm}{6r} \] 4. **Calculating the Change in Energy**: The work done (or energy required) to move the satellite to the new orbit is the change in energy, which can be calculated as: \[ \Delta E = E_{\text{final}} - E_0 \] Substituting the values we calculated: \[ \Delta E = \left(-\frac{GMm}{6r}\right) - \left(-\frac{GMm}{2r}\right) \] \[ \Delta E = -\frac{GMm}{6r} + \frac{GMm}{2r} \] 5. **Finding a Common Denominator**: To combine these fractions, we need a common denominator. The common denominator between 6 and 2 is 6: \[ \Delta E = -\frac{GMm}{6r} + \frac{3GMm}{6r} \] \[ \Delta E = \frac{2GMm}{6r} = \frac{GMm}{3r} \] 6. **Expressing in Terms of \( E_0 \)**: We know that \( E_0 = -\frac{GMm}{2r} \). To express \( \Delta E \) in terms of \( E_0 \): \[ \Delta E = \frac{GMm}{3r} = \frac{2}{3} \left(-\frac{GMm}{2r}\right) = \frac{2}{3} E_0 \] ### Final Answer: The energy required to move the satellite to a circular orbit of three times the radius of the initial orbit is: \[ \Delta E = \frac{2}{3} E_0 \]

To solve the problem, we need to determine the energy required to move a satellite from its initial circular orbit to a new circular orbit that is three times the radius of the initial orbit. ### Step-by-Step Solution: 1. **Understanding the Energy of a Satellite in Orbit**: The total mechanical energy \( E \) of a satellite in a circular orbit is given by the formula: \[ E = -\frac{GMm}{2r} ...
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