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What would be the value of acceleration due to gravity at a point 5 km below the earth's surface ? `(R_(E) = 6400 km, g_(E) = 9.8 "ms"^(-2))`

A

`9.6 " ms"^(-2)`

B

`9.79 " ms"^(-2)`

C

`9.89 " ms"^(-2)`

D

`10 " ms"^(-2)`

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The correct Answer is:
To find the value of acceleration due to gravity at a point 5 km below the Earth's surface, we can use the formula for gravitational acceleration at a depth \( h \): \[ g_d = g_e \left(1 - \frac{d}{R}\right) \] where: - \( g_d \) is the acceleration due to gravity at depth \( d \), - \( g_e \) is the acceleration due to gravity at the Earth's surface (given as \( 9.8 \, \text{m/s}^2 \)), - \( d \) is the depth below the Earth's surface (5 km in this case), - \( R \) is the radius of the Earth (given as \( 6400 \, \text{km} \)). ### Step 1: Convert the depth and radius to the same units Since the depth \( d \) is given in kilometers, we need to convert it to meters: \[ d = 5 \, \text{km} = 5000 \, \text{m} \] And the radius of the Earth: \[ R = 6400 \, \text{km} = 6400000 \, \text{m} \] ### Step 2: Substitute the values into the formula Now we can substitute \( g_e \), \( d \), and \( R \) into the formula: \[ g_d = 9.8 \left(1 - \frac{5000}{6400000}\right) \] ### Step 3: Calculate the fraction Calculate the fraction: \[ \frac{5000}{6400000} = 0.00078125 \] ### Step 4: Substitute back into the equation Now substitute this value back into the equation: \[ g_d = 9.8 \left(1 - 0.00078125\right) \] \[ g_d = 9.8 \left(0.99921875\right) \] ### Step 5: Calculate \( g_d \) Now, calculate \( g_d \): \[ g_d \approx 9.8 \times 0.99921875 \approx 9.79 \, \text{m/s}^2 \] ### Final Answer Thus, the value of acceleration due to gravity at a point 5 km below the Earth's surface is approximately: \[ g_d \approx 9.79 \, \text{m/s}^2 \] ---

To find the value of acceleration due to gravity at a point 5 km below the Earth's surface, we can use the formula for gravitational acceleration at a depth \( h \): \[ g_d = g_e \left(1 - \frac{d}{R}\right) \] where: - \( g_d \) is the acceleration due to gravity at depth \( d \), ...
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