Home
Class 11
PHYSICS
Two identical thin ring each of radius R...

Two identical thin ring each of radius `R` are co-axially placed at a distance `R`. If the ring have a uniform mass distribution and each has mass `m_(1)` and `m_(2)` respectively, then the work done in moving a mass `m` from the centre of one ring to that of the other is :

A

`(Gm)/(m_(2)R)(sqrt(2)+1)m`

B

`(Gm(m_(1)-m_(2)))/(sqrt(2)R)(sqrt(2)-1)`

C

`(Gmsqrt(2))/(R)(m_(1)+m_(2))`

D

zero

Text Solution

AI Generated Solution

The correct Answer is:
To find the work done in moving a mass \( m \) from the center of one ring to the center of the other ring, we can follow these steps: ### Step 1: Understand the Setup We have two identical thin rings of radius \( R \) placed coaxially at a distance \( R \) apart. Each ring has a mass \( m_1 \) and \( m_2 \) respectively. We need to calculate the gravitational potential at the center of each ring. ### Step 2: Calculate the Gravitational Potential at Point A (Center of Ring 1) The gravitational potential \( V_A \) at the center of Ring 1 due to Ring 2 can be calculated using the formula: \[ V_A = -\frac{G m_2}{R} \] where \( G \) is the gravitational constant. ### Step 3: Calculate the Gravitational Potential at Point B (Center of Ring 2) Similarly, the gravitational potential \( V_B \) at the center of Ring 2 due to Ring 1 can be calculated using the distance \( \sqrt{2}R \) (the distance from the center of Ring 1 to the center of Ring 2): \[ V_B = -\frac{G m_1}{\sqrt{2}R} \] ### Step 4: Calculate the Change in Potential Energy The work done \( W \) in moving the mass \( m \) from the center of Ring 1 to the center of Ring 2 is equal to the change in gravitational potential energy: \[ W = m (V_B - V_A) \] Substituting the values of \( V_A \) and \( V_B \): \[ W = m \left(-\frac{G m_1}{\sqrt{2}R} - \left(-\frac{G m_2}{R}\right)\right) \] This simplifies to: \[ W = m \left(-\frac{G m_1}{\sqrt{2}R} + \frac{G m_2}{R}\right) \] ### Step 5: Simplify the Expression Factoring out \( G \) and \( m \): \[ W = \frac{G m}{R} \left(-\frac{m_1}{\sqrt{2}} + m_2\right) \] ### Final Result Thus, the work done in moving the mass \( m \) from the center of one ring to the center of the other is: \[ W = \frac{G m}{R} \left(m_2 - \frac{m_1}{\sqrt{2}}\right) \]

To find the work done in moving a mass \( m \) from the center of one ring to the center of the other ring, we can follow these steps: ### Step 1: Understand the Setup We have two identical thin rings of radius \( R \) placed coaxially at a distance \( R \) apart. Each ring has a mass \( m_1 \) and \( m_2 \) respectively. We need to calculate the gravitational potential at the center of each ring. ### Step 2: Calculate the Gravitational Potential at Point A (Center of Ring 1) The gravitational potential \( V_A \) at the center of Ring 1 due to Ring 2 can be calculated using the formula: \[ ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    DC PANDEY ENGLISH|Exercise (B) Chapter Exercises|31 Videos
  • GENERAL PHYSICS

    DC PANDEY ENGLISH|Exercise INTEGER_TYPE|2 Videos
  • KINEMATICS

    DC PANDEY ENGLISH|Exercise INTEGER_TYPE|10 Videos

Similar Questions

Explore conceptually related problems

Two identical thin rings each of radius R are coaxially placed at a distance R. If the rings have a uniform mass distribution and each has masses 2m and 4m respectively, then the work done in moving a mass m from centre of one ring to that of the other is

Two identical thin ring, each of radius R meters, are coaxially placed a distance R metres apart. If Q_1 coulomb, and Q_2 coulomb, are repectively the charges uniformly spread on the two rings, the work done in moving a charge q from the centre of one ring to that of the other is

Two identical thin ring, each of radius R meters, are coaxially placed a distance R metres apart. If Q_1 coulomb, and Q_2 coulomb, are repectively the charges uniformly spread on the two rings, the work done in moving a charge q from the centre of one ring to that of the other is

Two thin rings each of radius R are placed at a distance 'd' apart. The charges on the rings are +q and -q. The potential difference between their centres will be -

Find the out the moment of inertia of a ring having uniform mass distribution of mass M and radius R about an axis which is tangent ot the ring and a in the plane of the ring b . perpendicular to the plane of the ring.

Find the intensity of gravitational field at a point lying at a distance x from the centre on the axis of a ring of radius a and mass M .

Calculate the moment of inertia of a ring having mass M , radius R and having uniform mass distribution about an axis passing through the centre of the ring and perpendicular to the plane of the ring?

Three rings, each of mass m and radius r , are so placed that they touch each other. Find the moment of inertia about the axis as shown in Fig.

Consider a ring of mass m and radius r. Maximum gravitational intensity on the axis of the ring has value.

A particle of mass 1kg is placed at a distance of 4m from the centre and on the axis of a uniform ring mass 5kg and radius 3m . The work done to increase the distance of the particle from 4m to 3sqrt(3) m is

DC PANDEY ENGLISH-GRAVITATION-(C) Chapter Exercises
  1. Infinite number of bodies, each of mass 2kg, are situated on x-axis at...

    Text Solution

    |

  2. The universal law of gravitational is the force law known also as the

    Text Solution

    |

  3. The value of acceleration due to gravity at the surface of earth

    Text Solution

    |

  4. The escape velocity of a particle of a particle from the surface of th...

    Text Solution

    |

  5. If earth were to rotate on its own axis such that the weight of a pers...

    Text Solution

    |

  6. The earth moves around the Sun in an elliptical orbit as shown figure...

    Text Solution

    |

  7. The radii of two planets are respectively R1 and R2 and their densitie...

    Text Solution

    |

  8. The weight of an object is 90 kg at the surface of the earth. If it is...

    Text Solution

    |

  9. The escape velocity from earth is v(e). A body is projected with veloc...

    Text Solution

    |

  10. A satellite of mass m is circulating around the earth with constant an...

    Text Solution

    |

  11. Two identical thin ring each of radius R are co-axially placed at a di...

    Text Solution

    |

  12. If r is the distance between the Earth and the Sun. Then, angular mome...

    Text Solution

    |

  13. A spherical planet far out in space has a mass M(0) and diameter D(0)....

    Text Solution

    |

  14. A geostationary satellite is orbiting the earth at a height of 5R abov...

    Text Solution

    |

  15. When a satellite is moving around the earth with velocity v, then to m...

    Text Solution

    |

  16. A lauching vehicle carrying an artificial satellite of mass m is set f...

    Text Solution

    |

  17. Consider a satellite orbiting the earth as shown in the figure below. ...

    Text Solution

    |

  18. A body is projected vertically upwards from the surface of earth with ...

    Text Solution

    |

  19. Find the imaginary angular velocity of the earth for which the effecti...

    Text Solution

    |

  20. The mass of the moon is (1/8) of the earth but the gravitational pull ...

    Text Solution

    |