12 cells, each of emf `1.5` V and internal resistance of `0.5Omega`, are arranged in m rows each containing n cells connected in series, as shown. Calculate the values of n and m for which this combination would send maximum current through an external resistance of `1.5 Omega`.

24 cells, each of emf 1.5V and internal resistance is 2Omega connected to 12Omega series external resistance. Then,

Eight cells marked 1 to 8, each of emf 5 V and internal resistance 0.2 Omega are connected as shown. What is the reading of ideal voltmeter ?

Three identical cells, each of emf 2 V and internal resistance 0.2Omega are connected in series to an external resistor of 7.4Omega . Calculate the current in the circuit.

N cells each of e.m.f. E & internal resistance r are grouped into sets of K cells connected in series. The (N/K) sets ae connected in parallel to a load of resistance R, then,

100 cells each of emf 5V and internal resistance 1 Omega are to be arranged to produce maximum current in a 25 Omega resistance. Each row contains equal number of cells. Find the number of rows.

n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is

A battery of 20 cells (each having e.m.f. 1.8V and internal resistance 0.1Omega is charged by 220 volts and the charging current is 15A. Calculate the resistance to be put in the circuit.

Two cells of emfs 1.5 V and 2.0v having internal resistance 0.2 Sigma and 0.3 Sigma respectively are connected in parallel . Calculate the emf and internal resistance of the equivalent cell .

If n cells each of emf E and internal resistance rare connected in parallel, then the total emf and internal resistances will be

cells each of emf e and internal resistance r are joined in series to form a row and such rows are connected in parallel to form a battery of N = mn cells. If this battery is connected to an external resistance R . Show that current f flowing through the external resistance R is given by : I=(Ne)/(mR+nr)